Question 941153
The second expression is the difference of cubes.  You can look for the formula or try to derive it.


The first expression best managed by factoring each term completely, first.

{{{27*2*x^2+9*9x+3*2*5}}}
{{{3*9*2x^2+3*3*9x+3*10}}}
{{{3(18x^2+27x+10)}}}
You can try searching for combinations, but I will use the Discriminant.
Discriminant, {{{27^2-4*18*10=9}}}, which means the roots of the quadratic part are {{{(-27-sqrt(9))/36}}}  and {{{(-27+sqrt(9))/36}}};
{{{-30/36}}} and {{{-24/36}}};
{{{-5/6}}}  and  {{{-2/3}}};
Whole factorization therefore, {{{highlight(3(x+5/6)(x+2/3))}}}.