Question 941098
Water Freezes at 0 Celsius and 32 Farenheit. Water boils at 100 C and 212 F.
A. Find the equation of the line that relates F to C. Use F=Y and C=X and you were given two points on the line, the first point is (0,32).
:
Use the slope formula: m = {{{((y2-y1))/((x2-x1))}}}
Assign the x,y points as follows, 
x1=0; y1=32
x2=100; y2=212
Find the slope (m)
m = {{{((212-32))/((100-0))}}} = {{{180/100}}} = {{{9/5}}}
y = mx + b, the slope intercept equation
When x=0, y=32, therefore b = 32
y = {{{9/5}}}x + 32; is the equation
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B. Use the equation to find F for C=16. 
y = {{{9/5}}}(16) + 32 
y = 28.8 + 32
y = 60.8 degrees Farenheit
Use the equation to find C for F=100.
{{{9/5}}}x + 32 = 100
{{{9/5}}}x  = 100 - 32
{{{9/5}}}x = 68
x = {{{5/9}}}68
x = 37.78 Celsius
;
C. At what temperature are Fahrenheit and Celsius the same (where does F=C)?
write the equation
y = {{{9/5}}}y + 32
y - {{{9/5}}}y = 32
{{{-4/5}}}y = 32
y = {{{-5/4}}}(32)
y = -40 degrees, F & C are the same