Question 941053
Let {{{ d }}} = the distance in feet from work to home
Find Leah's head start:
17:54 minus 17:46 = 8 min
Let {{{ s }}} = the daughter's walking speed in ft/min
{{{ 1.5s }}} = Leah's walking speed
{{{ d[1] = 1.5s*8 }}} 
{{{ d[1] = 12s }}} ft
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Start a stop watch when daughter leaves
add their speeds to find when they meet
{{{ d - 12s = ( s + 1.5s )*t }}}
{{{ t = ( d - 12s ) / (2.5s) }}}
{{{ t = d/(2.5s) - 4.8 }}} minutes
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They meet at 17:46 + d/(2.5s) - 4.8