Question 941010
 One integer is 18 more than twice another number,
a = 2b + 18
 if their product is equal to -36, what are the integers?
a*b = -36
Therefore
b(2b+18) = -36
2b^2 + 18b + 36 = 0
simplify, divide by 2
b^2 + 9b + 18 = 0
Factors to
(b+3)(b+6) = 0
Two solutions
b = -3
b = -6
then when b = -3
a = 2(-3) + 18
a 12
when b = -6
a = 2(-6) + 18
a = 6
 Give one of the two pairs of numbers for which this is true.
a=12, b=-3 or a=6, b-6