Question 940978
Work backwards,
{{{(x-4)(x+2/3)=x^2+(2/3)x-4x-8/3}}}
{{{(x-4)(x+2/3)=x^2-(10/3)x-8/3}}}
Since the coefficient for the {{{x^2}}} term is {{{3}}}, multiply by {{{3}}}.
{{{3(x-4)(x+2/3)=3x^2-10x-8}}}
So then,
{{{k=-10}}}
and
{{{p-2=-8}}}
{{{p=-6}}}