Question 79998
from the second equation
***  y=2x/3-8/3=(2x-8)/3
substitute this for y in first equation
x/5+1/2((2x-8)/3)=4
x/5+(2x-8)/6=4
find common denominator (by multiplying x/5 times 6 and (2x-8)/6 times 5, since 30 would be the common denominator)
so you get 
(6x+10x-40)/30=4
16x-40=120
16x=160
x=10
now substite this value for x in equation marked ***
now you have
y=(2(10)-8)/3=(20-8)/3=12/3=4

thus x=10 and y=4

Good Luck!