Question 941016
Let the 4 consecutive odd integers be:
{{{ n }}}, {{{ n+2 }}}, {{{ n + 4 }}}, and {{{ n + 6 }}}
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given:
{{{ n + 4 + n + 6 - 2*( n + n + 2 ) = 96 }}}
{{{ 2n + 10 - 2*( 2n + 2 ) = 96 }}}
{{{ 2n + 10 - 4n - 4 = 96 }}}
{{{ -2n + 6 = 96 }}}
{{{ -2n = 90 }}}
{{{ n = -45 }}}
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The number are:
-45, -43, -41, -39
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check the answer:
{{{ n + 4 + n + 6 - 2*( n + n + 2 ) = 96 }}}
{{{ -41 - 39 - 2*( -45 -43 ) = 96 }}}
{{{ -80 - 2*( -88 ) = 96 }}}
{{{ -80 + 176 = 96 }}}
{{{ 96 = 96 }}}
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Hope you can follow it