Question 940926
find the numbers
a, b, c
 such that the product of the first and the second is 28,
ab = 28
a = 28/b
 product of the second and third is 84
bc = 84
c = 84/b
 and the product of the third and the first is 48.
ac = 48
Replace a with (28/b) and c with (84/b)
{{{28/b}}} * {{{84/b}}} = 48
{{{2352/b^2}}} = 48
which is
48b^2 = 2352
b^2 = {{{2352/48}}}
b^2 = 49
b = {{{sqrt(49)}}}
b = 7
then
a = 28/7 = 4
and
c = 84/7 = 12
:
The numbers: 4, 7, and 12