Question 940925
16.) 

to find the slope of the line that is perpendicular to the line {{{3x-5y=20}}}, first write this line in slope-intercept form {{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept:

{{{3x-5y=20}}}....solve for {{{y}}}

{{{3x-20=5y}}}

{{{3x/5-20/5=5y/5}}}

{{{(3/5)x-4=y}}} or

{{{y=(3/5)x-4}}} 

so, the slope of this line is: {{{m=(3/5)}}}

the slope {{{m[p]}}} of the line that is perpendicular to this line will have a slope negative reciprocal of the slope {{{m=(3/5)}}} which is

{{{m[p]=-(1/(3/5))}}}

{{{m[p]=-(5/3)}}}