<PRE><B>Question 940870</B>
One number = x the other X+6
When twice the larger 2(x+6) is added to three times the smaller (3x)the result is 32. So 2(x+6)+3x=32
2x+12+3x=32 Multiply out the 2
5x+12=32 Combine
5x+12-12=32-12 Subtract 12 from both sides
5x=20
5x/5=20/5  Divide both sides by 5
x=4 ANSWER One number is 4, the other is 4+6=10 
CHECK:
Twice the larger added to 3 x the smaller =32
2(10)+3(4)=32
20+12=32
32=32</PRE>