Question 940693
The square of X is equal to 4 times the square of Y:
{{{X^2=4Y^2}}}
X is equal to 1 more than twice Y:
{{{X=2Y+1}}}
substitute for X , solve for Y:
{{{(2Y+1)^2=4Y^2}}}
{{{4Y^2+4Y+1=4Y^2}}}
{{{4Y+1=0}}}
{{{4Y=-1}}}
{{{Y=-1/4}}}
Find X:
{{{X=2Y+1=2(-1/4)+1=1/2}}}
CHECK:
{{{X^2=4Y^2}}}
{{{(1/2)^2=4(-1/4)^2}}}
{{{ 1/4=4(1/16)}}}
{{{1/4=1/4}}}