Question 940679
find the vertices,foci amd asymptotes of each hyperbola. 
{{{x^2/121 - y^2/144 = 1}}}
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Given hyperbola has a horizontal transverse axis.
Its standard form of equation:{{{(x-h)^2/a^2-(y-k)^2/b^2=1}}}, (h,k)=center
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For given equation:x^2/121-y^2/144=1
center:(0,0)
a^2=121
a=√121=11
b^2=144
b=12
vertices: (0±a,0)=(0±11,0)=(-11,0) and (11,0)
foci: c^2=a^2+b^2
c^2=121+144=265
c≈16.3
foci: (0±c,0)=(0±16.3,0)=(-16.3,0) and (16.3,0)
asymptotes: straight lines that go thru center and of the form : y=mx+b, m=slope, b=y-intercept
slopes of asymptotes=±b/a=±12/11
equation of asymptote with negative slope: 
y=-12x/11 (y-intercept,b=0)
equation of asymptote with positive slope: 
y=12x/11 (y-intercept,b=0)