<PRE><B>Question 940636</B>
A service station has 36 octane and 60 octane gasoline. How many liters of each gasoline should be mixed to provide 12 liters of 50 octane gasoline for a chemistry experiment?
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Equation::
octane + octane = octane
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36x + 60(12-x) = 50*12
36x + 60*12 - 60x = 50*12
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24x = 10*12
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x = (1/2)10 = 5 liters (amt. of 36 octane needed)
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12-x = 7 liters (amt. of 60 octaine needed)
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Cheers,
Stan H.
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