Question 940558
{{{4x^2-9=0}}}

{{{(2x)^2-3^2=0}}}

{{{(2x-3)(2x+3)=0}}}

solutions:

if {{{(2x-3)=0}}} => {{{2x=3}}} => {{{x=3/2}}}=> {{{highlight(x=1.5)}}}
and

if {{{(2x+3)=0}}} => {{{2x=-3}}} => {{{x=-3/2}}}=> {{{highlight(x=-1.5)}}}


{{{ graph( 600, 600, -10, 10, -10, 10, 4x^2-9) }}}