Question 940492
The second side of a triangular deck is 5 feet longer than the shortest side and a third side that is 5 feet shorter than twice the length of the shortest side. if the perimeter of the deck is 68 feet, what are the lengths of the three sides? 
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let x=length of shortest side
x+5=length of 2nd side (5 ft longer than shortest side)
2x-5=length of 3rd side (twice the length of shortest side-5
x+x+5+2x-5=68
4x=68
x=17
x+5=22
2x-5=29
length of shortest side=17
length of 2nd side=22 
length of 3rd side=29