Question 940485
{{{dB=10log(I/10^-12)}}}, where I is intensity in watts per square meter
First convert to {{{watts/m^2}}}
{{{(2.53x10^-5watts/cm^2)*(100^2 cm^2/m^2)=0.253watts/m^2}}}
Then plug in:
{{{dB=10log((0.253watts/m^2)/(10^-12))}}}=104 dB