Question 940456

it's not quite clear what you have here:

if you have {{{3x+2/7-4x/7}}} then

{{{7*3x+(2*7)/7-7(4x)/7}}}

{{{21x+2-4x}}}

{{{17x+2}}}

but, if you have {{{(3x+2)/7-4x/7}}} then

{{{(3x+2-4x)/7}}}

{{{(2-x)/7}}}