Question 940358
Guessing that you have this expression, 
{{{(27a^12)^(-4/3)}}}


steps can go


{{{(3^3*a^12)^(-4/3)}}}


{{{(3^3)^(-4/3)*(a^12)^(-4/3)}}}


{{{3^(-4)*a^(-12(4/3))}}}


{{{3^(-4)a^(-16)}}}


{{{highlight(1/(3^4*a^16))}}}