Question 940327


{{{(x^3/x^-1)^(-1/4)}}}...first write {{{x^-1}}} as {{{1/x}}}


{{{(x^3/(1/x))^(-1/4)}}} then do this part {{{x^3/(1/x)=(x^3/1)/(1/x)=(x^3*x)/(1*1)=x^3*x^1=x^(3+1)=x^4}}}

{{{(x^4)^(-1/4)}}} now, when you have this ^(-1/4) means {{{(1/fourth_ root_of_a_number)}}}; so, you will have

{{{root(4,x^4)}}} ...since you have {{{x^4}}} under fourth root, you just cancel root and exponent and result is:

{{{x}}}