Question 79875
{{{ln(e,x + 4) - log(e,x + 1) = log(e,x)}}}
{{{ln(e,(x + 4)/(x + 1)) = log(e,x)}}}
{{{(x + 4)/(x + 1) = x}}}
{{{x + 4 = x(x + 1)}}}
{{{x + 4 = x^2 + x}}}
{{{0 = x^2 - 4}}}
{{{0 = (x - 2)(x + 2)}}}
x = 2 and x = -2
You can not take the log of a negative number. Answer: x = 2