Question 79876
{{{log(4,2x + 1) = log(4,x - 3) + log(4,x + 5)}}}
{{{log(4)(2x + 1) = log(4,(x - 3)(x + 5))}}}
{{{log(4)(2x + 1) = log(4,x^2 + 2x - 15)}}}
{{{2x + 1 = x^2 + 2x - 15}}}
{{{0 = x^2 - 16}}}
{{{0 = (x + 4)(x - 4)}}}
x = -4 and x = 4
You can not take a log of a negative number. Answer: x = 4