Question 940134

let Anita’s age be {{{A}}} and Basilio’s age be {{{B}}}

if Anita is {{{4 (1/2)=4.5}} years older than Basilio, then we have

 {{{A=B+4.5}}} ...........eq.1

if  three times Anita’s age (or {{{3A}}})  added to six times Basilio’s age (or {{{6B}}}) is {{{36}}}, then we have:

{{{3A+6B=36}}}.....eq.2...substitute {{{B+4.5}}} for {{{A}}} from eq.1

{{{3(B+4.5)+6B=36}}}.......solve for {{{B}}}

{{{3B+13.5+6B=36}}}

{{{9B=36-13.5}}}

{{{9B=22.5}}}

{{{B=22.5/9}}}

{{{highlight(B=2.5)}}}  or {{{highlight(B=2(1/2))}}}

go to  {{{A=B+4.5}}} ...........eq.1 plug in {{{B}}}

{{{A=2.5+4.5}}} 

{{{highlight(A=7)}}} 

so,  Anita is {{{7}}} years old, and Basilio is {{{2}}}{{{1/2}}} years old