Question 940103
No, your answer for a) is incorrect.
Always check your solution in the original equation.
{{{2(3)+5=15}}}
{{{6+5=15}}}
{{{11=15}}}
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{{{2d+5=15}}} Subtract 5 from both sides.
{{{2d=10}}} Divide both sides by 2.
{{{d=5}}}
Checking,
{{{2(5)+5=15}}}
{{{10+5=15}}}
{{{15=15}}}
True, good solution.
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{{{20e-4=0}}} Add 4 to both sides.
{{{20e=4}}} Divide both sides by 20.
{{{e=4/20}}} Factor out 4 from numerator and denominator.
{{{e=1/5}}}