Question 940081
One liter of 10% alcohol is mixed with 30% of alcohol
1 liter = 1000 mililiter
one liter solution contain 10% alcohol 
that means alchol amount of 1st solution =10% of 1000 mililiter= 100 ml
another liter solution contain 30% alcohol 
that means alchol amount of 2nd solution =30% of 1000 mililiter= 300 ml
if we mixed both the solution
then 02 liter soluton contain = 100 ml + 300 ml = 400 ml alcohol

percentage of 400 ml alcohol in 02 liter solution is = 400/2000×100=20%

then the percentage of alcohol in the resulting mixture 20%

answer
krutartha