Question 939985
{{{f(x) = -2x^2 + 5x + 3}}}

{{{0 = -(2x^2 - 5x - 3)}}}

{{{0 = -(2x^2 - 6x+x - 3)}}}

{{{0 =-((2x^2 - 6x)+(x + 3))}}}

{{{0 = -(2x(x-3)+(x-3))}}}

{{{0 = -(2x+1)(x-3)}}}

{{{-(2x+1)(x-3)=0}}}

solutions:

if {{{(2x+1)=0}}}=> {{{2x=-1}}}=>{{{x=-1/2}}}

if {{{(x-3)=0}}}=> {{{x=3}}}


{{{ graph( 600, 600, -10, 10, -10, 10, -2x^2 + 5x + 3) }}}