Question 939942
{{{(1/81)^(4m+1)>(1/27)^5*m}}}

Ok, let's simplify this using indices
{{{1/81 = 1/3^4 = 3^-4}}} and {{{1/27= 1/3^3 = 3^-3}}}
Knowing the above, we can simplify the inequality to become
{{{3^(-4*(4m+1)) > 3^(3*5*m)}}}
Since the bases on both sides are equal, let's take the inequalities of the powers alone
-4*(4m+1)>-3*5m
-16m-4>-15m
Let's add 16m to both sides
-16m+4+16m>-15m+16m
4>m
m<4 since it has been reversed