Question 939936
The sin is negative only in the 3rd and 4th quadrants,
so you are limited to those
{{{ sin( theta ) = - sqrt(3) / 2 }}}
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For a 30-60-90 triangle, the {{{ sin( 60 ) = sqrt(3) / 2 }}},
so one angle is {{{ 180 + 60 = 240 }}} in the 3rd quadrant
to make the sin negative
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The other angle whose sin is {{{ -sqrt(3)/2 }}} is
{{{ 360 - 60 = 300 }}} degrees in the 4th quadrant
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If you draw it, it's not confusing