Question 939643
Let the length of the field be l and its width be w
From the first statement, {{{l = 2*w + 5}}}
 Perimeter of the field is 334 yards
And perimeter of rectangle = 2*l +2*w = 334

Now substituting for l, {{{2* (2*w + 5) +2*w =334}}}
4*w+10+2*w = 334
6*w = 334-10
6*w = 324,
w = 324/6 = 54
Also, l=2*w + 5= 2*54+5= 113
Therefore, the dimensions are (l,b) = (113,54)