Question 79786
As in the pervious graph that I posted, this equation is in SLOPE-INTERCEPT FORM, y=mx+b.  In this case {{{y=(1/2)x -1 }}}, the y-intercept is -1, and the slope m={{{1/2}}}={{{(RISE)/(RUN) }}}, which means that the RISE =1, and the RUN =2.  Start graphing the y-intercept by going DOWN 1 unit on the y-axis.  Put a point there.  Now, with your pencil on this point, go UP 1 unit, then go to the RIGHT 2 units, and put another point.  Connect the dots.  It should look like this:

{{{graph(300,300, -10, 10, -10, 10, (1/2)x-1 ) }}}


R^2 at SCC