Question 939539
2x + 5y + 1 = 0   0r y = (-2/5)x - 1/5
....
New Perpendicular Line:  m = 5/2
***Using point-slope form, {{{y - y[1] = highlight_green(m)(x - x[1])}}}P(-1,-2)
y + 2 = (5/2)(x+1)
y = (5/2)x + 5/2 - 4/2
y = (5/2)x  + 1/2
0r
5x - 2y = -2  Standard Form