<PRE><B>Question 939535</B>
Find the standard score (z) such that the area above the mean and below z is about 34% of the area under the normal curve
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Draw the picture so you can see what you are doing.
Note:: The area to the right is 0.5000-0.3400 = 0.1600
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Use a z-table or calculator to find the z-value with a right tail of 0.16
I use a TI-84:: z = invNorm(0.84) = 0.9946
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 Using the z (a) notation (Identify the value of a used within the parenthesis)
 Area=0.92 to the left of z
Ans: a = invNorm(0.92) = 1.4051
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Cheers,
Stan H.
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