Question 939323
f(x)=2-x
{{{ g(x)=sqrt(3)-x}}}
  fog(x)=  f(g(x))
         ={{{ f(sqrt(3)-x)}}}
            = {{{2-(sqrt(3)-x)}}}
            ={{{2-sqrt(3)+x}}}
 we need to piut x=-1  to find out fog(-1)
  fog(-1)= {{{ 2-sqrt(3)+(-1)}}}
         = {{{1-sqrt(3)}}}