Question 939324
 f(x)=2-x
{{{ g(x)=sqrt(3)-x}}}
  fog(x)=  f(g(x))
         ={{{ f(sqrt(3)-x)}}}
            = {{{2-(sqrt(3)-x)}}}
            ={{{2-sqrt(3)+x}}}
 we need to piut x=-2  to find out fog(-2)
  fog(-2)= {{{ 2-sqrt(3)+(-2)}}}
         = {{{-sqrt(3)}}}