Question 939385
let x, y be the present  ages of Mia and Max

Mia was 12 years older than Max
       x= y+12
 5 years ago , mia age  =  x-5
 5 years ago ,Max age  = y-5
 sum  =  (x-5)+(y-5)
          =x+y-10
 sum equals to 28
   x+y-10 = 28
     x+y = 28+10
  x+y = 38
    put  x= y+12 in above equation
   (y+12)+y = 38
        2y+12= 38
    2y =38-12
    2y  = 26
   divide with 2 on both sides
 {{{ 2y/2 =26/2}}}
    y= 13
  x = 13+12= 25
 Mia's age (x)=  25 years
 Max's age (y)=  13