Question 939229
given:

{{{b = (1/3)a}}} => {{{a = 3b}}} 
and 
{{{c = 2b}}} 
then

{{{a^2/c^2 = (3b)^2 / (2b)^2}}}

{{{a^2/c^2  = (3/2)^2(cross(b)1/cross(b)1)^2}}}

{{{a^2/c^2  = (3/2)^2}}} 

{{{a^2/c^2 = 9/4}}}

{{{a^2/c^2  = 2.25}}}