Question 939201
a = time to the store of first car
b = time to the store of second car
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s = d/t
t = d/s
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time to the store of first car:
a = 0.25/15
a = 0.016666666666 hour
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time to the store of second car:
b = 0.25/30
b = 0.008333333333 hour
but the second car leaves 20 seconds after the first car:
b = 0.008333333333 hour + (20 seconds * 1/(60*60) hour/seconds)
b = 0.013888888888 hour
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answer:
the second car gets to the store first
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