Question 79666
Let x=width
Then 2x+3=length

Area of a rectangle =Length times Width or A=L*W

So our equation to solve is:

10=x(2x+3)  get rid of parens

10=2x^2+3x  subtract 10 from both sides and rearrange

2x^2+3x-10=0  quadratic in standard form; solve using the quadratic formula

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (-3 +- sqrt( 9+80 ))/(4) }}} 
{{{x = (-3 +- sqrt( 89 ))/(4) }}} 
{{{x = (-3 +- 9.433)/(4) }}} 
{{{x = (-12.433)/(4) }}} and
{{{x = (+6.433)/(4) }}} 

So
{{{x =-3.1}}} ---------------------discount negative lengths
and

{{{x =1.6}}} inches-----------------width

{{{2x+3 =2(1.6)+3=6.2}}}inches----------- length 

CK

A=10=(1.6)*(6.2)
~10=10



Hope this helps----ptaylor