Question 939051
Let x,y be the  larger  and smaller number respectively
One hails of large number is x/2
3  times the other numbers is 3x
One half of a larger number, plus three times another number is equal 9
 {{{(x/2)+3y=9}}} ......eq1
two thirds a larger number minus twice a smaller number is 6
{{{(2/3)x-2y=6}}}}......eq2
We need to solve above equations
*[invoke linear_substitution "x", "y", (1/2),3,9,(2/3),-2,6]