Question 939001
{{{ g(t) =  sqrt(1-6^t)}}}
     1-6^t cannot be negative   as sqrt of negative term is not valid
   {{{1-6^t >=0}}}
      {{{1>=6^t}}}
 hence t should be negative as 6 ^ negative  = negative
 negative term is always less than 1 

 if   t= 0
       6^0 = 1
   hence t =0 is also the solution
    hence domain  =  all negative terms + 0
                    = ( -infinity,0)