Question 939043
  let x, y be the larger & smaller number respectively

One half of a larger number, plus three times another number is equal to 9
   {{{ (x/2)+ 3*y  = 9 }}}   ...............eq(1)
 Two thirds a larger number minus twice a smaller number is 6. 
 {{{(2/3) *x - 2y  =6}}} ...............eq(2)
 we  need to solve above equations to get the  answers
*[invoke linear_substitution "x", "y", (1/2), 3, 9, (2/3), -2, 6 ]
result: larger number  = 12
  smaller number  = 1