Question 938981
The expression can too easily be misunderstood.  If what you wrote is rendered to appear more normal in notation, this is it:


{{{X^2(2x^2+1)^2/(x-1)*(4x^3-6x^2+x-2)/x(x-1)(2x^2+1)}}}


Is that what you have?


"Yes"....
The rendered expression has a couple of obvious factors of 1.  You could eliminate {{{x/x}}} and {{{(2x^2+1)/(2x^2+1)}}}.   You still want to try to factorize the cubic expression factor found in the numerator.  


If you know polynomial division, you should divide 4x^3-6x^2+x-2  by  x-1. If remainder is 0, then you have just found two factors of 4x^3-6x^2+x-2.

....In fact, remainder is -3.  This means that no other possible factors to check for it in the denominator.


You have then once simplifications done,
{{{x(2x^2+1)(4x^3-6x^2+x-2)/(x-1)^2}}}
The last thing to do is multiply the polynomials of the numerator, and multiply  (square)  the binomials of the denominator.