Question 79583
:
{{{((4x^3-10x^2+6x))/((2x^3+x^2-3x))}}}
:
factor out 2x in the numerator and x in the denominator:
{{{(2x(2x^2-5x+3))/(x(2x^2+x-3))}}} = {{{(2(2x^2-5x+3))/((2x^2+x-3))}}}; x's cancels out
:
Both the numerator and denominator will factor:
{{{(2(x-1)(2x-3))/((x-1)(2x+3))}}} = {{{(2(2x-3))/((2x+3))}}}; canceled the (x-1)'s