Question 938704
the standard slope-intercept form for an equation of a line is 
{{{y = highlight_green(m)x + highlight(b)}}}  where m is the slope and b the y-intercept.  
-4x + 3y = 8   0r y = (4/3)x + 8/3, m = (4/3)
....
Line perpendicular(Slope is the negative reciprocal):  m = (-3/4)  
...
***Using point-slope form, {{{y - y[1] = highlight_green(m)(x - x[1])}}}P(0,0)
y-0 = (-3/4)(x-0)
y = (-3/4)x
Standard Form:   3x + 4y = 0