Question 938477
<pre>
Let h = the hundreds digit
Let t = the tens digit
Let u = the units or ones dogit
</pre>
I am a number with 2 more tens than ones. 
<pre>
t = u+2
</pre>
I have 5 more ones than hundreds.
<pre>
u = h+5
</pre>
the sum of my digits is 18. 
<pre>
t+h+u = 18

{{{system(t = u+2,u=h+5,t+h+u=18)}}}

Solve the second for h, u-5=h

Substitute (u+2) for t, and (u-5) for h, in t+h+u = 18

      (u+2) + (u-5) + u = 18
              u+2+u-5+u = 18
                   3u-3 = 18
                     3u = 21
                      u = 7

Substitute 7 for u in u-5 = h

                    7-5 = h
                      2 = h 

Substitute 7 for u in t = u+2
                      t = 7+2
                      t = 9

Answer:  [h][t][u] = 297  
                      
Edwin</pre>