Question 938461

{{{5}}}---{{{8}}}---{{{11}}}--- {{{14}}}---{{{17}}}

----{{{3}}}----{{{3}}}----{{{3}}}----- {{{3}}}---common difference

in first row we have common difference {{{3}}}, means function is linear and previous term is {{{3}}} less then next term:

if we have  {{{5}}} for first term, using common difference it is {{{3*1+2}}}

second term is {{{8}}} , using common difference it is {{{5+3=3+2+3=3*2+2}}}

third term is {{{11}}} , using common difference it is {{{8+3=3*2+2+3=3*3+2}}}

and so on

in general, we can write an explicit equation as:

{{{a[n] = 3n+2}}} (for all terms given) where {{{n}}}= {{{1}}},{{{2}}}{{{3}}}....