Question 938080
Let {{{n}}} be the 3-digit number, and the value of the number.
Placing a {{{4}}} at the end of that 3-digit number turns it into
a 4-digit number whose value is {{{10n+4}}} .
If doing that incleases the value by {{{4828}}}, then
{{{10n+4-n=4828}}}--->{{{9n+4=4828}}}--->{{{9n=4828-4}}}--->{{{9n=4824}}}--->{{{n=4824/9}}}--->{{{highlight(n=536)}}} .