Question 938287
{{{y=mx+b}}} ...this is a slope-intercept form  equation of the linear function where {{{m}}} is a slope and {{{b}}} is y-intercept 

if you have {{{y=(1/4)x + 2}}} means {{{m=1/4}}} and {{{b=2}}} ( means a line crosses y-axis at {{{2}}} if {{{x=0}}})

so, we already have one point and it is ({{{0}}},{{{2}}})

since a line is defined by two points, we need one more point to graph this line

easiest way is to find x-intercept or value of {{{x}}} that makes {{{y=0}}}

so, {{{y=(1/4)x + 2}}} plug in {{{y=0}}} and solve for {{{x}}}

{{{0=(1/4)x + 2}}}...since you have a fraction with denominator {{{4}}}, multiply all terms by {{{4}}} to eliminate a fraction

{{{4*0=4*(1/4)x + 4*2}}}

{{{0=cross(4)(1/cross(4))x + 8}}}

{{{0=1*x + 8}}}

{{{0=x + 8}}}

{{{0-8=x + 8-8}}}

{{{-8=x }}}

then, other point is: ({{{-8}}},{{{0}}})

now plot these two points and draw a line through:

{{{drawing( 600, 600, -10, 10, -10, 10,
circle(0,2,.13),circle(-8,0,.13),
locate(0,2,p(0,2)), locate(-8.4,0.6,p(-8,0)), 
graph( 600, 600, -10, 10, -10, 10, (1/4)x + 2)) }}}