Question 937897
Hello!
I am confused on how to factor this 6th degree polynomial:
f(x) = 6x^4-13x^3-27x^2+40x-12
How would I group them? I tried to rearrange them but I can't seem to find a way to figure it out.
Any help is greatly appreciated. Thank you!

- Marterlo
<pre><font face = "Tohoma" size = 4 color = "indigo"><b>You can use the RATIONAL ROOT THEOREM twice, and along with POLYNOMIAL LONG DIVISION,
you should obtain the factors of polynomial: {{{6x^4 - 13x^3 - 27x^2 + 40x - 12}}} as: {{{highlight_green((x - 3)(x + 2)(3x - 2)(2x - 1))}}}, and so:
{{{f(x) = 6x^4 - 13x^3 - 27x^2 + 40x - 12}}} becomes: {{{f(x) = (x - 3)(x + 2)(3x - 2)(2x - 1)}}}, from which the solutions to the equation,
or the ROOTS of the equation can be obtained. 
By the way, it's a 4<sup>th</sup> degree polynomial, not a 6<sup>th</sup> degree polynomial. Hence, there are 4 ROOTS, or 4 solutions, or 4 zeroes.      
You can do the check!! 
===================
If you need a complete and detailed solution, let me know!!
</font face = "Tohoma" size = 4 color = "indigo"></b>Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously. 

For FREE info and answers to questions about the ASVAB exam, the NYS 3 – 8 city/state wide exams,GENERAL
MATH and HOMEWORK QUESTIONS, or MATH QUESTIONS related to the Regents Integrated Algebra, 
Regents Geometry, Regents Algebra 2/Trigonometry, SHSAT, COOP/HSPT/TACHS, PSAT, SAT, ACT, SSAT/ISEE,
GRE, CLEP, and the TASC/GED, you can visit: http://asvabstudyzone.freeforums.net/.