Question 937858
the cube root of {{{x^6/250}}}


{{{root(3,(x^6/250))}}} .......since {{{x^6=x^2*x^2*x^2=(x^2)^3}}} and {{{250=5*50=5*5*10=5*5*5*2=5^3*2}}}, we have


={{{root(3,((x^2)^3)/(5^3*2))}}}


={{{root(3,(x^2)^3)/(root(3,(5^3)root(3,2)))}}}



={{{x^2/5root(3,2)}}}