Question 937217
t = {{{sqrt(x^2+2^2)/2}}} + {{{((6-x))/5}}}
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Find the derivative of t wrt x:
dt/dx = {{{x/(2*sqrt(x^2+4)) - 1/5 = 0
{{{5x - 2sqrt(x^2+4) = 0}}}
{{{5x = 2sqrt(x^2+4)}}}
{{{25x^2 = 4*x^2+4)}}}
{{{x^2 16/21}}}
{{{x = 4sqrt(21)/21}}}
x =~ 0.87287 miles
distance = 6 - x